All categories

3 years ago

Determine the missing side lengths

Mathematics

2 answers:

svetlana [45]3 years ago

6 0

Answer:

Given that is a 45-45 triangle, the hypotenuse should be <em>x</em> $\sqrt{2}$ , so in this case. The hypotenuse should be 3 $\sqrt{2}$ , and the other side lengths 3. I see no other way of it going other than that one; I hope I helped at least a bit!

Step-by-step explanation:

Oksanka [162]3 years ago

4 0

Answer:

base =3in and hypotenuse =3√2

Step-by-step explanation:

relationship between perpendicular and hypotenuse is given by sin angle

sin 45=p/h

sin45=3in/h

h=3in/sin45=3√2 inch

relationship between perpendicular and base is given by tan angle

tan45=P/b

b=3in/tan45=3in

You might be interested in

$7.50 for 5 pounds ?

larisa [96]

Assuming you are trying to get price per pound.

Divide 750 by 5 which equal 150 or $1.50

8 0

2 years ago

Whats The Answer Marking Brainliest, Please explain your answer:D..............................Please HELP!!!!!!!!!!!!!!!!!!!!!!

GREYUIT [131]

Answer: D.

Step-by-step explanation: Every min is 60 sec. Multiply that by 4, and then add that by 30. That equals 270 and that is lower than Wyatt's time.

6 0

3 years ago

Read 2 more answers

Can someone please help and explain

Nuetrik [128]

Answer:

Step-by-step explanation:

that is the least common denominator

3 0

3 years ago

Read 2 more answers

Someone help plz!!!

rewona [7]

20 I think good luck

4 0

3 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$