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Temka [501]
2 years ago
8

Pleaseeeeee hellpppppp

Mathematics
1 answer:
HACTEHA [7]2 years ago
4 0

Answer:

3:4

The answer is that divide it and multiply it by 2 and 3 respectively

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Evaluate each function following the specification.
telo118 [61]

Answer:

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

\#4 \  a. \ h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. Yes, <em>x ≠ 2</em>

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

h(x) = \dfrac{x}{x - 2}

By substitution, we get;

h(-1) = \dfrac{-1}{(-1) - 2} = \dfrac{-1}{-3} = \dfrac{1}{3}

\therefore h(-1) = \dfrac{1}{3}

h(0) = \dfrac{0}{0 - 2} = \dfrac{0}{-2} =0

\therefore h(0) =0

h(2) = \dfrac{2}{2 - 2} = \dfrac{2}{0} = \infty

\therefore h(2) =  \infty

h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>

3 0
3 years ago
Help please I will mark brainlest
rodikova [14]

Answer:

5\sqrt{7}

Step-by-step explanation:

\frac{30\sqrt{14} }{6\sqrt{2} }

Cancel out 6 in both numerator and denominator.

\frac{5\sqrt{14} }{\sqrt{2} } Rationalize the denominator of \frac{5\sqrt{14} }{\sqrt{2} } by multiplying the numerator and denominator by \sqrt{2}.

\frac{5\sqrt{14}\sqrt{2}  }{(\sqrt{2})^{2}  }

The square of  \sqrt{2} is 2

Factor 14=2 × 7. Rewrite the square root of the product \sqrt{2x7} as the product of square roots \sqrt{2}\sqrt{7}.

\frac{5\sqrt{2}\sqrt{7}\sqrt{2}   }{2}

Multiply \sqrt{2} and \sqrt{2} to get 2.

\frac{5x2\sqrt{7} }{2}

Cancel out 2 and 2.

5\sqrt{7}

Hope it helps and have a great day! =D

7 0
1 year ago
Read 2 more answers
9. Find the Highest Common Factor of
netineya [11]
C. 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

1,000: 2, 4, 5, 10, 20

The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

24: 1, 2, 3, 4, 6, 8, 12, 24

880: 1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

20 and 880: 2, 4, 8

8 is the Highest Common Factor.

E. Do the same thing with E.

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

90 and 1000: 2, 5, 10

10 is the Highest Common Factor.

3 0
2 years ago
Read 2 more answers
Pablo's retirement party will cost $8 if he invites 4 guests. If there are 6 guests, how
mezya [45]

Answer:

$12

Step-by-step explanation:

Step 1:

$8 : 4 = x : 6

Step 2:

4x = 48

Answer:

x = 12

Hope This Helps :)

6 0
3 years ago
Which of these is the area of a sector of a circle with r = 18”, given that its arc length is 6π?
Igoryamba
22/7*18^2*6π/2π*18 = 169.65
4 0
3 years ago
Read 2 more answers
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