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White raven [17]
3 years ago
6

A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536  yards. The lengt

h of the field is 22 yards less than quadruple  the width. What are the dimensions of the playing field?
Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards

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Which line intersects the parabola y = x^2 + 6x-2 at two points?
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Answer:

C

Step-by-step explanation:

You find y-intercept x=0

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3 years ago
If you multiply 0.86 by 7.36, how many decimal places will be in the product?
AURORKA [14]

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4

Step-by-step explanation:

There are 4 numbers to the right of decimals in question.

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3 years ago
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8. What's the GCF of *<br> (1 Point)<br> 4x2 - 6x + 8
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Answer:2

Step-by-step explanation:

6 0
3 years ago
(5) Rhea ran 6 laps on a track. Each lap is 200 yards. Rhea's average speed for
sashaice [31]

Answer:

72 yd / min

Step-by-step explanation:

The first thing is to fully calculate the distance traveled, each lap is 200 yards and how 6 laps would be:

200 * 6 = 1200

Now, let's divide the race into how the statement tells us:

1200 * 2/3 = 800

1200 * 1/3 = 400

That is, in the first 800 yards it goes to 80 yd / min and then in the remaining 400 yards it goes to 60 yd / min, let's calculate the time Rhea lasted:

800/80 = 10 min

400/60 = 6,667 min

Which means that in total it would be:

10 + 6,667 = 16,667

In other words, Rhea took 16,667 minutes to travel 1,200 yards, so the speed would be:

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Therefore the average Rhea speed was 72 yd / min

7 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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