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White raven [17]
3 years ago
6

A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536  yards. The lengt

h of the field is 22 yards less than quadruple  the width. What are the dimensions of the playing field?
Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards

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