A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536 yards. The lengt
h of the field is 22 yards less than quadruple the width. What are the dimensions of the playing field?
1 answer:
Answer:
W = 58 yards, L = 210 yards
Step-by-step explanation:
P = 2 (L + W)
L = 4w - 22
P = 2 (4W - 22 + W)
536 = 8W - 44 + 2W
536 = 10W - 44
10 W = 536 + 44
10W = 580
W = 58 yards
Since L = 4W - 22
L = 4 (58) - 22
L = 232 - 22
L = 210 yards
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