A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536 yards. The lengt

Question

3 years ago

6

h of the field is 22 yards less than quadruple the width. What are the dimensions of the playing field?

1 answer:

Aleksandr [31] · Answer 1 · 2022-07-28T06:59:57+03:00

5 0

Answer:

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards