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Rainbow [258]
3 years ago
7

The temperature at a ski resort was 12°F at 5:00 A.M.

Mathematics
1 answer:
zimovet [89]3 years ago
4 0
22.5 i Hope I’m right

Sorry if this is wrong
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Bob purchase a bus pass card with 320 points,each weeks costs 20 points for unlimited bus rides
blagie [28]
It would be 20 points bcuz it says each week it costs 20 points for unlimited bus rides
8 0
3 years ago
Can someone help me please?
alekssr [168]

Answer:

SHEEESH

Step-by-step explanation:

sneaker meetup see who we boutta finesse

3 0
3 years ago
Do political science classes require less writing than history classes? The 55 randomly selected political science classes assig
tia_tia [17]

Answer:

No, political science classes does not require less writing than history classes.

Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 19.6 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 50 randomly selected history classes assigned an average of 20.2 pages of essay writing for the course. The standard deviation for these 50 classes was 3.3 pages.

<em>Let </em>\mu_1<em> = mean writing required by political science classes</em>

<em />\mu_2<em> = mean writing required by history classes</em>

SO, Null Hypothesis, H_0 : \mu_1-\mu_2\geq0  or  \mu_1\geq \mu_2    {means that political science classes require more or equal writing than history classes}

Alternate Hypothesis, H_A : \mu_1-\mu_2  or  \mu_1   {means that political science classes require less writing than history classes}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                     T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample average writing for political science course= 19.6 pages

\bar X_2 = sample average writing for history course= 20.2 pages

s_1 = sample standard deviation for political science classes = 4.8 pages

s_2 = sample standard deviation for history classes = 3.3 pages

n_1 = sample of selected political science classes = 55

n_2 = sample of selected history classes = 50

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }  =  \sqrt{\frac{(55-1)\times 4.8^{2}+(50-1)\times 3.3^{2}  }{55+50-2} }  = 4.154

So, <u><em>the test statistics</em></u>  =  \frac{(19.6-20.2)-(0)}{4.154 \times \sqrt{\frac{1}{55}+\frac{1}{50}  } }  ~  t_1_0_3

                                     =  -0.739

<em>Now at 0.01 significance level, the t table gives critical value of -2.367 at 103 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t as -0.739 > -2.367, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that political science classes require more or equal writing than history classes.

8 0
3 years ago
A retailer returned 2700 defective items to the manufacturer and received a credit for the retail price of $0.83 or 834/34 per i
Helga [31]

Answer:

credit gain by retailer is $2257.39

Step-by-step explanation:

Given data:

Retaile price 83 4/3 c or 84.33c

Let Discount rate 6/7

Discount amount = (6/7)% of 84.33 c = 0.7228 C

Net credit received = 84.33c - 0.7228c = 83.607c

Net credit received = 83.607 c

Item required  = 2700

Total discount = 2700 × 83.0607 = 225739.44c

Total discount = $2257.39

credit received by retailer is $2257.39

8 0
3 years ago
The sum of two numbers is 90. their difference is 12. what are the numbers?
Kay [80]

39 and 51

The way to figure this out is to divide 90 by two

45 now subtract six and add six to 45 to achieve a difference of 12

45 - 6 = 39

45 + 6 = 51

7 0
3 years ago
Read 2 more answers
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