Answer:
y = 18 / (x + 2)²
Step-by-step explanation:
Inversely proportional
y * (x + 2)² = k
when x=1, y=2
k = 2 * (1 + 2)²
k = 18
-----------------------
y * (x + 2)² = 18
Divide both sides by (x + 2)²
y = 18 / (x + 2)²
Answer:
Step-by-step explanation:
First you do the parentheses so the -3 x 8n= -24 and -3 x -5= 15
so it will look like this. -24n+15-2n=8n-21
Now combine like terms the -24n-2n.
-26n+15=8n-21 now subtract 8n now it will look like this
-34n+15=-21 now -15 from -21
-34n=-36
now if you want n by its self divide -34 and -36
Not A.(17 is a common factor)
B. only common factor is 1
not C (7 is a common factor)
D. only common factor is 1
Both B and D are relatively prime.
Answer:
m = (ps - b - uxs/t) / ux/t - p
Step-by-step explanation:
ux/t +b/m+s =p
multiplying throughout by (m+s) we get:
ux/t(m+s) + b = p(m+s)
open the brackets:
uxm/t + uxs/t + b = pm + ps
bring on one side of the equal sign all terms containg m, to make it the subject:
m(ux/t - p) = ps - b - uxs/t
m= (ps - b - uxs/t) / ux/t - p
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
