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Vsevolod [243]
3 years ago
15

Complete the function favoriteFlower(). Note that the program will not run as is because the function is incomplete. The purpose

of the function is to determine if the given flower is in the top three of my favorite flowers. The starter file defines a list of favorite flowers that is ordered most favorite to least favorite. Please pass the flower name and the flower list as arguments in the function. The expected output is:
Computers and Technology
1 answer:
finlep [7]3 years ago
6 0

Answer:

What Language? Once you respond with a comment, I will be happy to write the code for you. I write code 24/7 (Because I have nothing better to do), so I will wait for you to comment. Also is there any pre-existing code?

Explanation:

You might be interested in
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
Write a program that prompts the user to enter positive integers (as many as the user enters) from standard input and prints out
julia-pushkina [17]

Answer:

Here is the JAVA program that prompts the user to enter positive integers from standard input and prints out the maximum and minimum values:

import java.util.*;

public class Ex0603 {

   public static void main(String[] args) { //start of main function

   Scanner in = new Scanner(System.in); //creates Scanner class object to take input from user

   int minimum = 0; //stores the minimum of the integers

   int maximum = 0; //stores the minimum of the integers

   int num; //stores the positive integer values

   System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

   num = in.nextInt();//scans and reads the input integer value from user

   minimum = num;  //assigns value of num to minimum

   while(true) {//while loop keeps prompting user to enter a positive integer

       System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

       num = in.nextInt();//scans and reads the input integer value from user

       if(num <=0)//if the user inputs a negative integer or 0

           break; //breaks the loop

       if (num > maximum) {//if the value of positive integer is greater than the maximum of value

           maximum = num; } //assigns that maximum value of num to maximum variable

       if (num < minimum) {//if the value of positive integer is less than the minimum of value

           minimum = num; //assigns that minimum value of num to minimum       }    }            

   System.out.println("The maximum integer is : " + maximum); //displays the maximum of the positive integers

   System.out.println("The minimum integer is : " + minimum); }}   //displays the minimum of the positive integers

Explanation:

Here is the JAVA program that that prompts the user to enter an integer N, then reads N double values, and prints their mean (average value) and sample standard deviation:

import java.util.*;  

public class Ex0603 {  

public static void main(String[] args) { //start of main function

Scanner in = new Scanner(System.in);  //creates Scanner class object to take input from user

double integer= 0;  //to store the number of input values

double sum = 0;  //to store the sum of input numbers

double mean = 0;  //to store the average of numbers

double sd = 0;  //to store the standard deviation result

double variance = 0;  //to store the variance result

double sumSquare = 0;  //to store the sum of (num-mean)^2

int n = 0;  //to store the sample size N

   System.out.println("Enter an integer: ");  //prompts user to enter an integer that is how many elements user wants to input

   integer = in.nextInt();  //reads the value of integer from user

   double size=integer; // declares a double type variable and assigns value of int type variable integer to this double type variable size

   int i=0;  //used to point each element of the num array

   double num[] = new double[(int)size];  //declares an array to hold the numbers input by user

   while(integer>0){  //loop executes until value of integer is greater than 0

   System.out.println("Enter a number: "); // prompts to enter a number

   num[i] = in.nextDouble(); //reads double values

   sum += num[i];  //adds the values stored in num array

   i++;  //increments i to point to the next element in num array

   n++;  //increments n to count the total number of elements

  integer--; //decrements integer value at each iteration

   mean = sum / n;    }  //compute the average of values

   i=0;  

    while(size>0){  //loop executes until value of size exceeds 0

       sumSquare += Math.pow(num[i]-mean,2); //takes the sum of square difference between each element of num array and value of mean

       i++; //increments i

      size--;   }  //decrements size

variance = sumSquare / (n-1);  //compute variance by dividing the result of sum of the squares of their differences from the mean by n-1

   sd = Math.sqrt(variance);  //computes standard deviation by using sqrt function which takes the sqrt of the result of variance computed above

System.out.println("Average value is: " + mean+ " and the standard deviation is " + String. format("%.2f", sd));   }} //displays the average of numbers stored in mean variable and value of standard deviation is displayed up to 2 decimal places

Screenshots of both programs and their outputs is attached.

7 0
3 years ago
40 POINTS I NEED THESE ANSWERS ASAP GIVE ME THE RIGHT ASNWER AND ILL PUT YOU AS THE BRAINLIEST
Law Incorporation [45]
Having a filling system and keeping a clean desk is good time management tips (True)

Your wrists should be low,relaxed and resting on the frame of the keyboard while typing (False)

A correctly formatted memo will have a complimentary closing? (False)

Which professional business memo part is keyed first?
D.) TO

to type a capital letter "T" the typist will hold the right shift key with the right little finger, and then strike "t" with the left pointer (first) finger. (True)

in a standard block style letter, key the date to print ___ from the top edge of the page
D.) Double space (DS)

A search engine can help link you to information on how to format a buisness letter. (True)
7 0
3 years ago
If somebody is using a laptop at a coffee shop, how are they likely connected to a network?
marusya05 [52]

Answer:

by signing into the wifi network they have

Explanation:

4 0
3 years ago
What are the most recent attacks on computer security that you face this month? Use the Internet to search for the latest attack
grigory [225]

Answer:

Now a days every thing can be done on the internet easily but this internet has various drawbacks with that as the most of our personal information we share on internet these days so if anyone attacks on your server then he/she can easily access all the private information including financial details and this attack is known as cyber attack. there are various ways to attack on the internet some of them are-

1.Malware- it is shortly known as the malicious software, malware can be described as worms, viruses, trojans these all are variety of malware which provide root access to the attacker by which they can control the system remotely.

2.phising- This is a technique by which the criminals craft emails to fool a target into taking some harmful action. The recipient might be tricked in downloading malware that disguised as an important document for instance or argued toclick on that link that takes them to a fake website where they can get the password which are necessary for any transaction.

3.Ransomware- This is like a malware which is stored in the computer and easily encrypt all the necessary files of the victim's computer and after that they demand some ransom to decrypt it.

4.SQL injection- This is the process by which the SQL command gets injected by the attacker into the victim's system so that the attacker can easily gather all the necessary information which they want to take control on the system.

These attacks are very dangerous for the system because the attacker can get all the necessary information about the user and can easily harm him/her by getting their personal information.

There are various steps to prevent these attacks which are-

I.secure your hardware- The user has to prevent their hardware from lost or steal. protect all devices with a complicated password, share that password with the device user only.

II.Encrypt and backup data- You have to prevent your data by making the backup of the necessary files so that if any of your information gets lost then you can retrieve it from your backup.

III. create a security focused workplace- Employees are the most common ways of breaching of the data as many don't recognise the external threats the internal one breaches the security and it cause the loss of the information.

some latest viruses are-

1.cyborg ransomware-This virus is present in the floppy disk which is used by the user and can cause the count of time the system reboot. it's new variant is present in windows 10.

2.Gobrut-This is also one of the latest viruses it is capable enough to detect weak passwords and can cause loss of information.

3.jokeroo-This virus works as the ransomware their author spread it in the computer system which will encrypt the files and for decrypting it they demand ransom for that.

4.Trojan Glupteba- Once this virus enters the system the user cannot know that the system is infected and it will slowly communicates with the IP of the system which results in loss of the confidential information.

Most vulnerable platforms are-

1.Social engineering- The social networking sites has most of your personal information of the user which can be used by the attacker to get the necessary information.

2.cloud computing services- More companies use to store their most of the information on the cloud which is used by the attacker to get the confidential passwords which can cause loss of the essential information.

Explanation:

6 0
3 years ago
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