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irinina [24]
3 years ago
14

The following diagram shows a parallelogram 100 degrees what the size of angle A ​

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

its probley either 90 or 100 degrees

Step-by-step explanation:

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Compute the following radical.<br> sq root 144
lara31 [8.8K]

we are given

\sqrt{144}

Firstly, we will find all possible factors of 144

144=2\times 2\times 2\times 2\times 3\times 3

we can also write as

144=(2\times 2)^2\times (3)^2

now, we can put exponent to over entire term

144=(2\times 2\times 3)^2

now, we can replace 144

\sqrt{144}=\sqrt{(2\times 2\times 3)^2}

now,  sqrt will get cancelled with square

and we get

\sqrt{144}=(2\times 2\times 3)

now, we can simplify it

\sqrt{144}=(4\times 3)

\sqrt{144}=12.............Answer


3 0
3 years ago
When a trend line is drawn on a scatterplot, there are 4 points above the trend line. About how many points should be below the
scoundrel [369]
There is no exact rule for lines of best fit. However, in general, there should be roughly the same amount above as below. So, if we are following this rule, there should be about 4 below as well. 
5 0
3 years ago
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As shown in the diagram of the right triangles below, Triangle: ABC ~ Triangle: DEF, AB = 7x, BC = 4, DE = 7, EF = x. What is th
charle [14.2K]

since triangles are similar

4/x = 7x/7

=》 4/x = x

=》x^2 = 4

=》 x = 2

for right triangles a^2 = b^2+c^2

DF^2 = 7^2+2^2 = 53

=》 DF = 7.28

perimeter of DEF = 7 +2+7.28 = 16.28

8 0
3 years ago
Which of the following graphs represents the equation x &gt;-3y+9
enot [183]
Hello,
Please, see the attached file.
Thanks.

5 0
3 years ago
You are standing above the point (5,5)(5,5) on the surface z=15−(2x2+2y2)z=15−(2x2+2y2). (a) in which direction should you walk
Marianna [84]
Since the surface is the top part of a sphere centred on the origin, the directions of steepest descent are any vector originating from the origin (0,0).

At (5,5), the direction would be dictated by the line joining (5,5) and the origin (0,0), i.e. along <5,5> or equivalently along <1,1>.

You can also go through vector calculus to arrive at the same result.

6 0
4 years ago
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