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stellarik [79]
3 years ago
7

Explain how using equivalent ratios is like adding fractions with unlike denominators

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0
It's kind of like division and mutliplycation I guess
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What nis the answer to n divided by 4 = 16
chubhunter [2.5K]

Answer:

Step-by-step explanation:

n/4 = 16

n = 16 × 4

n = 64

hope this helps

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4 years ago
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The sample mean is a statistic. True or false​
ruslelena [56]

Answer:

true

Step-by-step explanation:

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3 years ago
I need help w #5 first to answer will be marked brainliest!! Plz and thank you :)
mojhsa [17]

Answer:

1+1+2

Step-by-step explanation:

I'm the first one to answer to mark me Brainless!

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3 years ago
Among all rectangles that have a perimeter of 182, find the dimensions of the one whose area is largest.
Evgen [1.6K]

Answer:

<em>The largest rectangle of perimeter 182 is a square of side 45.5</em>

Step-by-step explanation:

<u>Maximization Using Derivatives</u>

The procedure consists in finding an appropriate function that depends on only one variable. Then, the first derivative of the function will be found, equated to 0 and find the maximum or minimum values.

Suppose we have a rectangle of dimensions x and y. The area of that rectangle is:

A=x.y

And the perimeter is

P=2x+2y

We know the perimeter is 182, thus

2x+2y=182

Simplifying

x+y=91

Solving for y

y=91-x

The area is

A=x.(91-x)=91x-x^2

Taking the derivative:

A'=91-2x

Equating to 0

91-2x=0

Solving

x=91/2=45.5

Finding y

y=91-x=45.5

The largest rectangle of perimeter 182 is a square of side 45.5

6 0
4 years ago
Math IIIB Performance Task: Piecewise-Defined Functions
meriva

9514 1404 393

Explanation:

a) see the attachment for a graph (red curve)

__

b) The piecewise defined function can be ...

  \displaystyle C(x)=\begin{cases}0&0\le x\le 1\\5&1

__

c) The new cost function is ...

  \displaystyle C(x)=\begin{cases}10&0\le x\le5\\x+5&5

The charge is a flat $10 for any period up to 5 hours, then $1 per additional hour after that, prorated for partial hours. There is apparently no upper limit on parking time as there was with the original function. (The graph shown goes beyond 15 hours; the domain of the original C(x) is 0 to 12 hours.) For reference, the new cost structure is shown in blue in the attachment.

_____

<em>Additional comment</em>

Under the new structure, costs are significantly higher for short-term parking, and lower once the term exceeds 6 hours.

7 0
3 years ago
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