Answer:
The skaters are 2.5 feet apart
Step-by-step explanation:
Firstly, please check attachment for diagrammatic representation.
To calculate the distance apart, this is same as the length PJ
To calculate this length, we can use the cosine rule as follows;
O^2 = P^2 + J^2 -2(P)(J)Cos 15
O^2 = 7^2 + 5^2 -2(7)(5)Cos 15
O^2 = 49 + 25 - 70Cos15
O^2 = 74 - 67.61
O^2 = 6.39
O = √6.39
O = 2.53
O = 2.5 feet to the nearest tenth of a foot
We have that
H(t)=-4.9t²<span>+50t + 2
we know that
</span><span>The initial height of the rocket, in meters is for t=0 sec
fot t=0
H(t)=</span>-4.9*0²+50*0 + 2------> H(t)=2 m
the answer is
The initial height of the rocket is 2 m
I think the answer is 24x-5
Answer:
2.7 x 5-6
Step-by-step explanation:
Answer:
thanks for the update and for your information and necessary to the room and I will be there at the same time I don't have a car so I can get a village to the room and I will be there at the same time I don't
Step-by-step explanation:
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