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3 years ago

If a number is divided by 10, which number cannot be the reminder

Mathematics

1 answer:

Shkiper50 [21]3 years ago

5 0

Answer:

Step-by-step explanation:

from 99 to 91 give us reminder

so reminders in 91 will be 1

92 will be 2

93 will 3

and so on to the 99 will be 9

but in 100 will not be there any reminder so, 10 cannot be the reminder

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solmaris [256]

C All real numbers except 5 and 0

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3 years ago

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If-2a > 6, then -a>3 -a<3 -a<-3 -a>-3

chubhunter [2.5K]

Answer:

a < - 3

Step-by-step explanation:

Given

- 2a > 6

Divide both sides by - 2, reversing the symbol as a result of dividing by a negative quantity, thus

a < - 3

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3 years ago

Which ordered pair is a solution of the equation? -x-4y=-10

Makovka662 [10]

Answer:

(2, 2 )

Step-by-step explanation:

To find a solution, choose any value for x, substitute into the equation and solve for y.

Choose x = 2, then

- 2 - 4y = - 10 ( add 2 to both sides )

- 4y = - 8 ( divide both sides by - 4 )

y = 2

Thus (2, 2 ) is a solution to the equation

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4 years ago

Read 2 more answers

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below: