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Zanzabum
3 years ago
12

Solve #5 Is the equation that you use P(t)=P(0)•e^rt ?

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0
P(t)=(p jk(t)),0 ~ t< 0
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Two times a number added to -4, subtracted from triple the sum of eight times the number and five
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Answer:

2x+(-4)-8x(3)-5

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HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
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Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

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We can take 4n common

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5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

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7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

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Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

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=-4(9n^3 + 3n +7)

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Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

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3 years ago
How can i get the answer to 5 X 70 = 5 X ____ tens = ____ tens = _____
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