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NeX [460]
3 years ago
7

The prices of two ratios are in the ratio x:y

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

4:1

Step-by-step explanation:

x+20 : y+20 = 5 : 2

(x+20)/(y+20) = 5/2

2(x+20) = 5(y+20)

2x+40 = 5y+100

2x = 5y+60 (1)

x-5 : y-5 = 5:1

(x-5)/(y-5) = 5/1

x-5 = 5(y-5)

x-5 = 5y-25

x = 5y-20 (2)

Solve (1) & (2) simultaneously,

2(5y-20) = 5y+60

10y-40 = 5y+60

5y = 100

y = 20

x = 5y-20

x = 5(20)-20 = 100-20

x = 80

x:y

80:20

4:1

Nitella [24]3 years ago
5 0
Answer: x:y = 2:5

Step-by-step explanation:
Given : The prices of two radios are in the ratio x:y
When the prices are both increased by £20, the ratio becomes 5:2
Then,
When the prices are both reduced by £5, the ratio becomes 5:1
Then,
Subtract (2) from (1), we get

Put this value in (2), we get

Now, the ratio of x:y=
Dividing 4 from both the numerator and denominator, we get
x:y= =2:5

Credit: JeanaShupp
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