The answer to the question asked above is 2006.
<span>Alienware introduce alienfx lighting zones into their pc's on 2006.</span>
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Answer:
Explanation:
Operator can be defined as
a character or characters which gives determination of actions that are needed to be performed/ considered. Operators are symbols that gives the compiler information to perform specific mathematical/logical manipulations.They are special type of functions, which are capable of taking one or more arguments, then produces a new value. Different types of operator are;
✓arithmetic operators(addition "+" substraction "-"
✓relational operators( greater than ">"
lesser than"<"
✓Logical operators.( Connective words/symbols such as AND, NOT, OR)
Arithmetic Operators: These include "+" (addition), "-" (subtraction), "*" (multiplication), "/" (division), "\" (integer
Answer:
punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']
def strip_punctuation(strWord):
for charPunct in punctuation_chars:
strWord = strWord.replace(charPunct, "")
return strWord
Explanation:
The function is defined with a single argument.
A for loop is ran to check each character of the the word.
If a punction mark is present as a character in the word, it is removed.
The same word is returned but without the punctuation marks.
C. you charge clothes you don’t really need on a high-interest store card
hope this helps :)
The program would not generate an error if the var_str list have up to 5 elements
<h3>How to determine the error?</h3>
The operation is given as:
Assign a value to that same index
This is represented as:
var_str[5] = "r"
The representations from the above code segment are
- List = var_str
- Index = 5
- Value = "r"
When a value is assigned to an index, the value at the index is updated to the new value, provided that the index exists in the list.
This means that the program would not generate an error if the var_str list have up to 5 elements
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