36, because 6^4 /6^2 is 6^2 and 6*6 (6^2) is 36
Answer:
1. 7:1
2. 1:8
Step-by-step explanation:
1. Start by counting the number of triangles. We see: 56 triangles. Then, count the hearts. We see: 8 hearts.
So, the ratio of triangles to hearts is 56:8 which we simplify to get: 7:1.
2. Start by adding triangles to hearts. We get: 56+8 which equals 64.
The amount of hearts equals 8 so the ratio of hearts to (hearts + triangle) is! 8:64 which equals 1:8.
step 1
Subtract 14 from 50
50-14=36
so
If you solve for p
the answer is the second option
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
Step-by-step explanation:
How do you know if side lengths form a Pythagorean triple?
Pythagorean triples may also help us to find the missing side of a right triangle faster. If two sides of a right triangle form part of a triple then we can know the value of the third side without having to calculate using the Pythagorean theorem. From the ratio, we know that it is a Pythagorean triple.
