Answer:
Length of the shadow of the pole is 6.93 metres
Step-by-step explanation:
Given:
Height of the pole = 4 m
The angle sun makes with the horizontal = 30 degrees
To Find:
Length of the shadow of the pole = ?
Solution:
The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta
Let x be the length of the shadow
According to the tangent ratio
On substituting the values,
x = 6.93 m
Step-by-step explanation:
x/3+x/6=7/2
We simplify the equation to the form, which is simple to understand
x/3+x/6=7/2
Simplifying:
+ 0.333333333333x+x/6=7/2
Simplifying:
+ 0.333333333333x + 0.166666666667x=7/2
Simplifying:
+ 0.333333333333x + 0.166666666667x=+3.5
We move all terms containing x to the left and all other terms to the right.
+ 0.333333333333x + 0.166666666667x=+3.5
We simplify left and right side of the equation.
+ 0.5x=+3.5
We divide both sides of the equation by 0.5 to get x.
x=7
Answer:
a'b' and ab are the same length
Step-by-step explanation:
they are both four squares long
Answer:
R = ![\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26-2%5C%5C1%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
P - Q + R = I ( I is the identity matrix )
![\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%5C%5C3%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
- ![\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%262%5C%5C4%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R = ![\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
( subtract corresponding elements )
![\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2-%28-2%29%264-2%5C%5C3-4%265-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R =
![\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%5C%5C-1%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R =
R = - =
6-3-3=-0 its - cause 3+3=6 and if 3-6-3 is o but its already o then just put a little line net to the zero
