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marusya05 [52]
3 years ago
8

While on a car trip with her family,Erin saw a sign that read,"Amarillo 100 miles,Lubbock 80 miles". She concluded that the dist

ance from Amarillo to Lubbock is 100-80=20

Mathematics
2 answers:
Artist 52 [7]3 years ago
5 0

Answer and Step-by-step explanation:

The answer to the question of maybe she was right or not depends on whether the two places mentioned, Amarillo and Lubbock, are in the same direction or not.

If Amarillo and Lubbock are in the same direction, then the distance between the two places truly is 100-80 = 20 miles and Erin is definitely right.

But if Amarillo and Lubbock are in opposite directions, then the distance between the two places is 100 + 80 = 180 miles and Erin is wrong with her 20 miles analysis.

Hope this Helps!!!

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Hence her conclusion distance between amarillo and lubbock is 20 miles is correct .

Step-by-step explanation:

Given :

The distance of Amarillo and Lubbock  as 100 and 80 miles respectively.

To find : Whether  her conclusion is Correct or Wrong?

Solution:

Consider a line on which she is travelling in one direction only since the sign board gives one direction information or on which direction u are travelling.

Now,

Consider a line segment as a AB   from sign board position as the starting point and Amarillo as the end point since it is at max distance i.e. 100 miles.

And Lubbock is 80 miles from the starting point ,

Hence Lubbock town or place will come before Amarillo .

So as the distance between is of cumulative  property ,

Refer the attachment ,

let point C be Lubbock and B be Amarillo ,A be starting point or sign board.

Hence

Distance holds cumulative property ,

take modulus values as ,

|B-C|=|C-B|

|100-80|=|80-100|=20 miles

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7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0​
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Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

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  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

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1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

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