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MaRussiya [10]
3 years ago
14

Solve the problem 8 - 2 9/14=

Mathematics
1 answer:
love history [14]3 years ago
8 0
Improper Fraction =75/14
Mixed Number=5 5/14
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The large square below has a side length of 8 inches, and the smaller white square inside the large square has a side length of
9966 [12]
The image is not attached with, but by reading the question it is obvious that the blue region lies inside the larger square and outside the smaller square. That is the region between the two squares is the blue region.

We know the dimensions of both squares, using which we can find the area of both squares. Subtracting the area of smaller square from larger one, we can find the area of blue square and further we can find the said probability.

Area of larger square = 8 x 8 = 64 in² 
Area of smaller square = 2 x 2 = 4 in²
Area of blue region = 64 - 4 = 60 in²

The probability that a randomly chosen point lies within the blue region = Area of blue region/Total area available

Therefore, the probability that a point chosen at random is in the blue region = 60/64 = 0.9375
7 0
3 years ago
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In a candy box, there are 5 times as many candies with nuts as candies without nuts. There are 30 candies in the box. How many c
Luden [163]

Answer:

90

Step-by-step explanation:

because there are 5 time as many candies with nuts as candies without nuts and there is 18 so it will be 18×5=90

6 0
3 years ago
Question is in the image
Mrac [35]
B is your answer. Just count it. That’s if black goes to blue.
4 0
3 years ago
Which expression is the factored form of -4.5n+3?
TEA [102]

The right ans is D.I am 100%sure.

if my ans was gelpful u can follow me.

5 0
3 years ago
Can you please show me how to do:
USPshnik [31]

Step-by-step explanation:

6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6

3 0
3 years ago
Read 2 more answers
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