Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer:
3
Step-by-step explanation:
8-5=3 meaning he sees 3 blue birds
Answer:
8m + 6
Step-by-step explanation:
18 + 4(m-3) + 4m = ? (distribute 4 into parenthesis)
18 + 4m -12 + 4m ( combine like terms)
8m + 6