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KonstantinChe [14]
3 years ago
5

Which equation could be the equation of this parabola?

Mathematics
2 answers:
grin007 [14]3 years ago
8 0
D, Because the equation must be in slope intercept (y=mx+b) and since it is going upwards (all positive nunbers) then the slope would be positive as well. I hope this helps!
nignag [31]3 years ago
5 0
Parabolas in the form of \sf y=x^2 open upwards or downwards.
Parabolas in the form of \sf x=y^2 open to the left or to the right.

Since this parabola opens upward, we know it must be in the form of \sf y=x^2. Also, if the coefficient of 'x' is positive, it opens upward, but if it is negative, it opens downward. This parabola opens upward, so we know that the coefficient of 'x' must be positive. Therefore, our answer must be D, \sf y=2x^2
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Tamiku [17]

Answer:

n

Step-by-step explanation:

the answer is -60, which is not an option

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2 years ago
This isn’t a work question but, how do I exactly get used to having online classes??
FinnZ [79.3K]

Answer:

well it might take some time to get used to going on the work and doing it. then soon or later you will be used to going on online classes

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me with this question. I will mark you brainliest. ​
solong [7]

<u>Answer:</u>

<em>Option D : $153</em>

<u>This is how I got that:</u>

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is <u>$51 </u>

<u />

But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:

<u>Mr. Anand must pay $153 or Option D</u>

<u></u>

<em>~That's All Folks~</em>

<em>-Siascon</em>

4 0
2 years ago
If your friend Doug is on a balcony and asks you to throw him a donut, how many stories up can he be and you would still feel co
Katena32 [7]
The building that I would imagine would be 40 stories, about 404 feet tall perhaps. If he were to throw the donut from that distance until the ground, catching it would be impossible. So no, I am not confident in catching the donut all the way there. 
8 0
3 years ago
A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
Katen [24]

Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

Step-by-step explanation:

The confidence interval for a proportion is given as [p +/- margin of error (E)]

p is sample proportion = 870/1,100 = 0.791

n is sample size = 1,100

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (z) at 5% significance level is 1.96.

E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024

Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767

Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

5 0
3 years ago
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