Answer:
4 4√3
Step-by-step explanation:
The given point (-3/5 , y) lies in the third quadrant.
It is also given that the point lies on a unit circle.
For a point (x,y) lying on a unit circle a and y are defined as:
x = cos θy = sin θSo, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ
sec θ is the reciprocal of cos θ.
So, sec θ = -5/3
Using Pythagorean identity we can first find sin θ.

Since the point lies in 3rd quadrant, both sin and cos will be negative.
So, now we can write:
Answers:sec θ = -5/3cot θ = 3/4
(This is the order in terms with the rule) 5 ... 8 ... 11 ... 14 ... 17 ... 20 ... 23 ... 26 ... 29 ... 32 ... So victor should say the number 32
How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
10mn
Step-by-step explanation:
