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xxTIMURxx [149]
3 years ago
7

Using v= u + at, find v, when u = 12, a = 5 and t = 7

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

v = 47

Step-by-step explanation:

v = u + at

Plug in the values.

v = (12) + (5)(7)

Multiply 5 and 7.

v = 12 + 35

Add

v = 47

Hope this helps!

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Find the gcf of 12, 18, and 84
Westkost [7]
Greatest Common Factor of 12,18,84.

Factors of 12:1,2,3,4,6,12
Factors of 18:1,2,3,6,9,18
Factors of 84:1,2,3,4,6,7, 12,14,21,28 42,84

The Greatest Common Factor (GCF) of all those three factors is 6.

The Greatest Common Factor is the greatest Factor in all the numbers. In this set, 12,84,84, 6 is the greatest, making it the Greatest Common Factor.

4 0
3 years ago
Read 2 more answers
The Russian ice breaker yamal can move forward through 2.3-meter-thick ice at a speed of 5.5 kilometers per hour. Write and solv
aleksandrvk [35]

82.5 / 5.5 = 15

15 hrs.

i think that should be the answer but i didn't use the 2.3 -meter-thick clue...

8 0
4 years ago
A carpenter is building a rectangular bookcase with diagonal braces across the back as shown the Carpender knows that angle ADC
Rudik [331]
I think I have the diagram right.
Let ADB = x, and then BDC = x+32.
x+x+32 = 90
2x = 58
x = 29 = ADB
so BDC = 61
6 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
4 years ago
An item on scale costs 15% of the original price. The original price was $29
Oxana [17]

Answer:

$4.35

Step-by-step explanation:

because 15% of 29 is 4.35

5 0
3 years ago
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