Ask question

Ask question

All categories

3 years ago

8

Pls help ASAP need help pls

2 answers:

e-lub [12.9K]3 years ago

5 0

Answer:

5. The raange Is 16

and the IQR is 1

6. Option 3. (C)

Step-by-step explanation:

telo118 [61]3 years ago

5 0

5. iqr=1, range=16
6. c, about half of the packages weigh 6 to 10 pounds. these are close to the median weight of 7 pounds

You might be interested in

8. A box is filled with candies in different colors. We have 40 white candies, 24 green ones, 12

Darya [45]

Answer:

$P(Green\ or\ Red) = 0.30$

Step-by-step explanation:

Given

$White = 40$

$Green = 24$

$Red = 12$

$Yellow = 24$

$Blue = 20$

Required

$P(Green\ or\ Red)$

The total numbe of candy is:

$Total = 40 + 24 + 12 + 24 + 20$

$Total = 120$

This probability is calculated as:

$P(Green\ or\ Red) = P(Green) + P(Red)$

For each, we have:

$P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}$

Take LCM

$P(Green\ or\ Red) = \frac{Green+Red}{Total}$

$P(Green\ or\ Red) = \frac{24+12}{120}$

$P(Green\ or\ Red) = \frac{36}{120}$

$P(Green\ or\ Red) = 0.30$

8 0

3 years ago

What is <br> 12а + 7x - За – 2х

kifflom [539]

Answer:

=12a-3a+7x-2x

=9a+5x

This is the answer.

Hope it helps you..

3 0

2 years ago

Read 2 more answers

BRAINLIEST!!<br> 17. Complete the statement about parallelogram ABCD.<br> ∠BDC ____

Vsevolod [243]

Answer:

∠ABD; Alternate Interior angles are congruent

Step-by-step explanation:

Sides AB and DC are congruent and parallel.

The transversal is line BD.

So considering this things, ∠BDC and ∠ABD are congruent through alternate interior angle rule

6 0

3 years ago

Read 2 more answers

How many degrees is one rotation that will put a regular pentagon back on top of itself?

Dmitriy789 [7]

If you rotate about the circumcentre of a regular polygon 72° it will overlap with the original image.

8 0

3 years ago

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours:

$t_{T} = t_{R}+t_{H}+t_{W}$

If Keenan runs and walks at constant speed, then equation above can be expanded:

$t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}$

Where:

$x_{R}$ , $x_{W}$ - Run and walk distances, measured in miles.

$v_{R}$ , $v_{W}$ - Run and walk speeds, measured in miles per hour.

Given that $x_{R}=x_{W} = 2.5\,mi$ , $v_{R} = 6\,\frac{mi}{h}$ , $v_{W} = 4\,\frac{mi}{h}$ and $t_{H} = 0.75\,h$ , the total time is:

$t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }$

$t_{T} = 1.792\,h$ ( $1\,h\,48\,m$ )

Kennan will be from home approximately an hour and 48 minutes.

7 0

3 years ago