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Arte-miy333 [17]
2 years ago
9

How would I solve this agai n

Mathematics
2 answers:
Sever21 [200]2 years ago
5 0
Break it up in to smaller shapes and add them together in this case you have the 3x3 square on the left a 2x5 rectangle in the middle top and a 4x4 square on the bottom (the ways it’s drawn looks like a rectangle but the number show it’s a square)

Find each of those areas and add together

3x3 + 5x2 + 4x4 = 9 + 10 + 16 = 35
Svetllana [295]2 years ago
3 0

Answer:

The area is 35 inches

Step-by-step explanation:

You will need to cut the shape into 3 parts

the 3 by 3

2 by 5

and 4 by 4

after that you multiply the numbers to get the area of the 3 parts.

The final step is to add them all up

( if you have more problems message me)

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Which numbers are factors of both 12 and 42?
FrozenT [24]

Answer:

12

Step-by-step explanation:

3 0
3 years ago
Pls just answer number 19 I will mark brainliest
bonufazy [111]
2 feet 7 inches.

5 feet - 2 feet is 3 feet
3 inches - 8 inches is - 5 inches.

just take the 5 inches from 3 feet to get 2 feet 7 inches.
7 0
3 years ago
The Pythagorean Theorem and Irrational numbers
Natalka [10]
49=16+x^2
x^2= 33
x= square root of 33
3 0
3 years ago
Kevin sold 2 unicycles and 1 bicycle for a total of $110. Greg sold 4 unicycles and 3 bicycles for a total cost of $268. What is
RSB [31]
Simultaneous Equations

2u +   b = $110
4u + 3b = $268

(x2) 4u + 2b = $220
(x1) 4u + 3b = $268

<em />If both the matching coefficients are the same, we subtract equation 2 from equation 1

2b - 3b = -b
$220 - $268 = $-48
-b = -$48
b = $48

If you want to find out what a unicycle costs...
Substitute b = $48 into the first equation
2u + $48 = $110
Balance the equation, whatever happens on one side, happens on the other.
2u + $48 (-$48) = $110 (-$48)
2u = $62
2u(/2) = $62(/2)
u = $31 
4 0
2 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

7 0
2 years ago
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