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lina2011 [118]
3 years ago
11

Can you plz answer these 2 questions​

Mathematics
1 answer:
vampirchik [111]3 years ago
5 0

Answer:

sorry cant help but how are u on lesson 71 im only 8

Step-by-step explanation:

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Find the complex zeros of x^3+27. write f in factored form
aliina [53]
x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0


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4 years ago
Taking an Uber ride in NYC has an initial fee of $2.55 with an additional charge of $1.75 per mile (we will ignore the small per
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what exactly am i solving for ?

Step-by-step explanation:

4 0
3 years ago
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Explain why 2a+3b=5ab
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That's not correct. The terms 2a and 3b are not like terms, so we cannot combine them to get 5ab. We simply leave it as 2a+3b.

If you had 2a+3a, then it would simplify to 5a

Similarly, 2b+3b = 5b

Or you could have 2ab+3ab = 5ab

The key is that the variable portions must match up to be able to add them.

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4 years ago
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Elena-2011 [213]

Answer:

Please see the attached images for explanation:

Step-by-step explanation:

Please let me know if you have any questions :)

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