Whats the sum of 5 feet 9 inches and 12 feet 3 inches

Whats the quotient for this?

iren2701 [21]

Answer:

Step-by-step explanation:

Divide 4378 by 15

From 4378 lets take the first two digits for division:

43/ 15

We know that 43 does not come in table of 15

So we will take 15 *2 = 30

43-30 = 13

The quotient is 3 and the remainder is 13

Now take one more number which is 7 with 13

137/15.

Now 137 does not come in table of 15

15*9 = 135

135-137 = 2

It means quotient is 9 and remainder is 2

Now take one more number which is 8 with 2

28/15

28 does not come in table of 15

15*1 = 15

28-15 = 13/15

Now the quotient is 1 and remainder is 13

Hence, the quotient of 4,378 is 291 and remainder is 13 ....

3 0

3 years ago

Michael has a fish tank that has a length of 7 inches,a width of 6 inches and a height of 8 inches. What is the total surface ar

White raven [17]

Answer:

292 inches^2

Step-by-step explanation:

So to start off this is a picture of the fish tank.

Next we will find the area of the bottom and top rectangles.

The side lenghts for those two is 7 and 8.

So the area of one is 56 and the area of 2 is 112 inches^2.

Now we will find the area of the left and right rectangles.

The side lenghts are 6 and 8.

So the area of 2 is 96 inches^2.

Now for the front and back rectangles.

The side lenghts for those two are 6 and 7.

So the area of both is 84 inches^2.

So after adding all the areas up the surface area is 292 inches^2.

6 0

2 years ago

The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter

JulsSmile [24]

Answer:

1) n=114

2) n=59

3) On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.2$ and $\alpha/2 =0.1$ . And the critical value would be given by:

$z_{\alpha/2}=-1.28, z_{1-\alpha/2}=1.28$

Part 1

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.06$ or 6% points, and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimate of $\het p$ we can use 0.5 as a good estimate, replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.06}{1.28})^2}=113.77$

And rounded up we have that n=114

Part 2

On this case we have a prior estimate for the population proportion and is $\hat p =0.85$ so replacing the values into equation (b) we got:

$n=\frac{0.85(1-0.85)}{(\frac{0.06}{1.28})^2}=58.027$

And rounded up we have that n=59

Part 3

On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

5 0

3 years ago

Compute the conditional probabilities P(A|B) and P(B|A).

Oksanka [162]

Answer:

Step-by-step explanation:

Good evening ,

P(A|B) = P(A∩B)/P(B)

P(B|A) = P(A∩B)/P(A)

:)

6 0

2 years ago

Given: tangent to Circle O.<br><br> If m C = 57°, then m BDR =

Romashka-Z-Leto [24]

∠BCD = 57°
∴ ∠BDR = ∠BCD = 57° (angle that meets the chord and the tangent is equi-angular to the angle at the alternate segment)

8 0

3 years ago