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Svetradugi [14.3K]
2 years ago
6

Leo is roller blading at w speed of 200 meters per minute.How long will it take him to roller-blade 1 km?

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0
1km = 1000m Then we would divide 1000 by 200 = 5


It would take leo 5 minutes to reach 1000km
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Help me solve -2+5n=4n+2
iris [78.8K]
Sorry for the messy handwriting
7 0
3 years ago
Help please!
bagirrra123 [75]

(d):  y = mx+n

m = -2/3 ⇒ y = (-2/3)x +n

A(-4,  6) ∈ d  ⇒ 6 = (-2/3)·(-4) +n ⇒ 6 = 8/3 +n ⇒

⇒ n = 6 - 8/3 ⇒ n = 10/3

Now, we have:

y = (-2/3)x +10/3


6 0
3 years ago
What two numbers multiply to the value of -10 and add to the value of -3
N76 [4]

Answer:

-5 and 2

Step-by-step explanation:

-5+2=-3

-5*2=-10

5 0
3 years ago
(X+8)(x-8) if necessary combine like terms
julia-pushkina [17]

Answer:

x² - 64

Step-by-step explanation:

Given

(x + 8)(x - 8)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x - 8) + 8(x - 8) ← distribute both parenthesis

= x² - 8x + 8x - 64 ← collect like terms

= x² - 64

3 0
2 years ago
You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
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