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Ierofanga [76]
3 years ago
15

Write the fraction as a percent if necessary round to the nearest tenth of a percent 5 2/5

Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Answer:

540\%

Step-by-step explanation:

we have

5\frac{2}{5}

step 1

Convert the mixed number to an improper fraction first

5\frac{2}{5}=\frac{5*5+2}{5}=\frac{27}{5}

step 2

To convert the fraction as a percent multiply by 100

\frac{27}{5}*100=27*20=540\%

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Galina-37 [17]
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4 years ago
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Vladimir [108]
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3 years ago
Ivanna drove 696 miles in 12 hours. At the same rate, how many miles would she drive in 7 hours?
Alexxandr [17]

Answer:

406

Step-by-step explanation:

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3 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
I need help to solve the system of equation by elimination.<br><br>x - 2y = -10<br>-5x + 4y = 14
Agata [3.3K]
Your answer is an ordered pair (2,6)
3 0
3 years ago
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