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3 years ago

Write the fraction as a percent if necessary round to the nearest tenth of a percent 5 2/5

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

Answer:

$540\%$

Step-by-step explanation:

we have

$5\frac{2}{5}$

step 1

Convert the mixed number to an improper fraction first

$5\frac{2}{5}=\frac{5*5+2}{5}=\frac{27}{5}$

step 2

To convert the fraction as a percent multiply by 100

$\frac{27}{5}*100=27*20=540\%$

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51 times the difference between a number and 21 is equal to the number plus 58.

Lerok [7]

51(x - 21) = x + 58

Distributive property

51x - 1071 = x + 58

Subtract x from both sides

50x - 1071 = 58

Add 1071 to both sides

50x = 1129

Divide both sides by 50

x = 22.58

7 0

3 years ago

Answer answer answer

Sergio [31]

Answer:

(m−5)(2m−2)

=(m+−5)(2m+−2)

=(m)(2m)+(m)(−2)+(−5)(2m)+(−5)(−2)

=2m2−2m−10m+10

=2m2−12m+10

6 0

3 years ago

the expression 1350(1.05)^t models the average wages, in dollar, in the us as a function of the number of years since 1930. what

barxatty [35]

Answer:

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Step-by-step explanation:

3 0

3 years ago

The position s(t) of a robot moving along a track at time t is given by s(t)=9t^2−90t+4.

Xelga [282]

The total distance traveled by the robot from t=0 to t=9 is 1422 units

Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.

Given that the position s(t) at any time t is given by the function:

s(t)=9t²−90t+4

The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9

Therefore:

$Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units$