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Crazy boy [7]
3 years ago
6

If caffeine reduces by about 10% per hour, how many hours h does it take for the amount of caffeine in a body to

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

7 hours

Step-by-step explanation:

Since, the final amount of caffeine formula would be,

A=P(1-r)^t

Where,

P = Initial value,

r = rate per period,

t = number of periods,

Here, r = 10% = 0.10, t = h, A = \frac{P}{2}

\frac{P}{2}=P(1-0.10)^h

\frac{1}{2}=(0.90)^h

Taking log both sides,

log 0.5 = log 0.90^h

log 0.5 = h log 0.90

\implies h = \frac{log 0.5}{log 0.9}=6.57881347896\approx 7

Hence, after 7 hours the amount of caffeine in a body to  reduce by half.

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The solution to the answer is as follows:

-7^-1 = -1/7

The expression without an exponent would be simplified to be -1/7.


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If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)( ) = . The check of the polynomial division problem shows that the product of
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Answer:

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

Step-by-step explanation:

Given

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

(x + 7) * (\ ) = [\ ]

Required

Complete the blanks

We have:

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

Rewrite as:

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You have $25 to spend on picking 21 pounds of three different types of apples in an orchard. The Empire apples cost $1.40 a
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Answer:

5 pounds of the Empire apples, 14 pounds of the Red Delicious apples, and 2 pounds of the Golden Delicious apples.

Step-by-step explanation:

Let's call the Empire apples weight at E, the Red Delicious at R, and the Golden Delicious at G. We know that the total weight must be 21 pounds so:

R + E + G = 21 (<em>equation 1</em>)

The total amount of spent must be $25, and the price given is per pound, so the priced paid is the cost multiplied by the weight:

1.40*E + 1.10*R + 1.30*G = 25 (<em>equation 2</em>)

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R = 2*(E + G)

E + G = R/2 (<em>equation 3</em>)

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So, E + G = 7

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G = 7 - E

G = 7 - 5

G = 2 pounds.

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