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maksim [4K]
2 years ago
9

In dry climates, people often dig wells to find additional sources of water

Chemistry
2 answers:
likoan [24]2 years ago
6 0

Answer:

Using the well could lower the water table throughout the area.

Explanation:

i just took a test and this was the answer

vekshin12 years ago
3 0

Answer:

D i think, sorry if its wrong

Explanation:

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3 years ago
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Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
Some volatile organic compounds can be detected by hydrogeologists in the field or labs because of the ______ emitted from the g
Vadim26 [7]

Volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.

<h3>What are volatile substances?</h3>

Volatile substances are substances which can easily vaporize or change to gaseous state.

Volatile substances can either be solids or liquids but are mostly liquids.

Example of volatile substances include ether, petrol, chocolate.

The presence of volatile substances can be detected by the gases they release which may have characteristic odors.

Therefore, volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.

Learn more about volatile compounds at: brainly.com/question/25403770

7 0
2 years ago
Refer to attachment please this is one of my study questions and im stuck
Reil [10]
Percentage yield= actual yield/theoretical yield x100
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15/22 x 100. Hope this helps!!
3 0
2 years ago
Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)
Ainat [17]

Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

mass N2 = 1.163*10⁻¹⁸ g


Hope that helps!

7 0
3 years ago
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