If f(x) varies directly with x2, and f(x) = 40 when x = 2, find the value of f(5).
1 answer:
Answer:
C.250
Step-by-step explanation:
If f(x) varies directly with x^2
f(x) = k * x^2
f(x) = 40 when x=2. Substitute these values in
40 = k(2)^2
40 = k*4
Divide by 4
40/4 = 4k/4
10 =k
f(x) = 10x^2
Now we want to find f(x) when x=5. Substituting
f(5) = 10 *5^2
f(5) = 10 *25
f(5) = 250
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