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VARVARA [1.3K]
2 years ago
12

A scientist invents a car that can travel for many hours without stopping for fuel. The car travels around a track at 46 miles a

n hour for 24 hours. At the end of the 24 hours, how far has the car traveled
Mathematics
1 answer:
melomori [17]2 years ago
6 0
Assuming the car is going at a constant speed, it will travel 1104 miles.

46*24=1104
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43-44 please and thanks
KatRina [158]
The easiest way to do the fractions is is you turn them to decimals.

43. >
44. >

You think it might be the othe way around, but it’s a negative. So if it’s -36 and -35, the -35 will be bigger. Think about the number line. -36 comes before -35.
4 0
3 years ago
A repair company’s charge for repairing a certain type of copy machine fits the model y = 47.38 + 0.617x where y is the number o
Tems11 [23]

Answer: 36.66min

Step-by-step explanation:

y = 47.38 + 0.617x

where y is the number of dollars

x is the number of minutes on the job

Given a value of y = $70, then

We substitute y = $70 in the equation.

70 = 47.38 + 0.617x

22.62 = 0.617x

X = 22.62/0.617 = 36.66min

6 0
2 years ago
What is the value of this expression? (−4)^4?
Charra [1.4K]
-4^4= -4*-4*-4*-4

-4*-4=16
16*-4=-64
-64*-4= 256

Final answer: 256
5 0
3 years ago
Prove that 25^11−5^19 is divisible by 31.
SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

4 0
3 years ago
Consider functions f and g in the table below.
nikitadnepr [17]

The answer is A.) x = 2

3 0
3 years ago
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