Answer:
5*2^3 = <em><u>30cm^3</u></em>
<em><u></u></em>
Volume = 2^3 = 6
5 cubes = multiply volume by 5
6*5 = 30
The answer is 30cm^3
Hope this helps
I'm guessing you are talking about the surface area of a cone?
<span>Also by length of the edge, do you mean slant height?
Here is the area formula for a cone:
Lateral Area = (<span>π<span> • r •<span> slant height)
Solving for "r" we get:
</span></span></span></span>
radius = Lateral Area / (<span>π<span> • </span></span><span><span>slant height)</span><span><span /></span></span>
When you calculate the radius, you can solve for the height by
height^2 = slant height^2 - radius^2
The length of BC is 12 or option B
Answer:
The second one.
Step-by-step explanation:
The width and height of the rectangle inscribed in the right triangle have a measure of 3.529 units.
<h3>How to find the dimensions of the rectangle of maximum area by optimization</h3>
In this problem we must use <em>critical</em> values and <em>algebraic</em> methods to determine to determine the dimensions of the rectangle such that the area is a <em>maximum</em>. The equation of the quadrilateral is formed by definition of the area of a rectangle:
A = w · h (1)
Where:
- w - Width of the rectangle.
- h - Height of the rectangle.
And the area of the entire triangle is:
0.5 · (5) · (12) = w · h + 0.5 · w · (12 - h) + 0.5 · (5 - w) · h
30 = w · h + 6 · w - 0.5 · w · h + 2.5 · h - 0.5 · w · h
30 = 6 · w + 2.5 · h
2.5 · h = 30 - 6 · w
h = 12 - 2.4 · w (2)
The quadrilateral of <em>maximum</em> area is always a square, then we must solve for w = h:
w = 12 - 2.4 · w
3.4 · w = 12
w = 3.529
Then, the width and height of the rectangle inscribed in the right triangle have a measure of 3.529 units.
To learn more on optimizations: brainly.com/question/15319802
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