Answer:
(5 x 15) + (3 x 15) = 120
Step-by-step explanation:
5 x 15 = 75
3 x 15 = 45
75 + 45 = 120
Hope this helps :)
Answer:
a)1.41666667 b)705882353 / 1000000000
Step-by-step explanation:
Random sampling. its where you pick or make a smaple at random
Answer:
f(3) = 15. Correct: D)
Explanation:
<u>Numeric Value of a Function</u>
The value of a function f(x) when x = a is calculated by replacing the x for a. We have the function:

It is required to find f(3), or the numeric value of f when x=3. Replace x for 3



A) Incorrect. f(3) is not 7
B) Incorrect. f(3) is not 10
C) Incorrect. f(3) is not 9
D) Correct. f(3) =15 as found above.
Answer:
1. 
2. 
3. 
Step-by-step explanation:
Given information:


(1)
We need to find the value of P(s₁|I).





Therefore the value of P(s₁|I) is
.
(2)
We need to find the value of P(s₂|I).





Therefore the value of P(s₂|I) is
.
(3)
We need to find the value of P(s₃|I).





Therefore the value of P(s₃|I) is
.