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umka21 [38]
3 years ago
7

What is the value of X in the triangle shown?

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

Step-by-step explanation:

take 45 degree as reference angle

using sin rule

sin 45=opposite/hypotenuse

1\sqrt{2}=x/16

x=16/\sqrt{2}

x=8\sqrt{2}

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Answer:

C

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The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.

x is the hypotenuse (side opposite of 90 degree angle).

We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

6^2 + 3^2 = x^2\\36 + 9 = x^2\\45 = x^2\\x=\sqrt{45}

<em>Now we can use property of radical  \sqrt{x}\sqrt{y}  =\sqrt{x*y}  to simplify:</em>

x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}

Correct answer is C

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