2^4 * 3 * 7
I hope this helps!
Since DH=HF you set x+3=3y
<span>GH=HE so 4x-5=2y+3 </span>
<span>This gives you a system and I solved by substitution so I got x alone in the first equation-> x=3y-3 </span>
<span>then I plugged this x into the second equation so </span>
<span>4(3y-3)-5=2y+3 </span>
<span>12y-12-5=2y+3 </span>
<span>12y-17=2y+3 </span>
<span>10y=20 </span>
<span>y=2 </span>
<span>plug y into the first equation to find x </span>
<span>x=3(2)-3 </span>
<span>x=6-3 </span>
<span>x=3 </span>
<span>c. x=3, y=2</span>
Lets solve for y
7x+3y=m
Step 1: Add -7x to both sides.
7x+3x+-7x=m+-7x
Step 2: Divide both sides by 3.

=

y=

m +

x
Given :
▪︎Measure of ∠R = 90°
▪︎Segment OR = Segment RN
Which will mean, ∠O = ∠N.
Thus :







Which means :
Measure of ∠O = 45°
Measure of ∠N = 45°
Therefore, the measures of these angles in ascending order = 45,45,90.