19.05*10 power 5
hope it helps

We use long division to divide
There is no x term in x^2 -1 so we put 0x
x + 1
----------------------------
x^2+0x-1 x^3+ x^2 + x+ 2
x^3+0x^2-x
-----------------------------(subtract the bottom from top)
x^2 +2x + 2
x^2 +0x - 1
--------------------------------(subtract the bottom from top)
2x + 3
-----------------------------------------
Quotient : x+1
Remainder : 2x+3
Answer:
X-19
Step-by-step explanation:
First you need to distribute the three into the numbers in the parenthesis,
(3 * x) + (3 * -5) - (2x + 4)
That then turns into,
3x - 15 - (2x + 4)
but we aren't done distributing yet, because the second set of parenthesis has a negative sign in front of it we also have to distribute that. (this is because the negative sign is really just -1)
3x - 15 + (-1 * 2x) + (-1 * 4)
that turns into,
3x - 15 - 2x -4
from here all we have to do is add like terms,
(3x - 2x) + (-15 + -4)
and that leaves us with: 1x -19 or x-19
Hope that helped :))
Answer:

Step-by-step explanation:
1) divide each term in the numerator by the term in denominator:
(remember when dividing subtract the smaller exponent from larger exponent
for example:
say a is the larger exponent, do 
x^4/x=x^3
5x^3/x=5x^2
3x^2/x=3x
so
x^3+5x^2+3x
hope this helps!