Answer:
Δe=0.578 kJ/kg
Explanation:
Given data
Velocity v₁=0 m/s
Velocity v₂=34 m/s
to find
Specific energy change Δe
Solution
The specific energy change is simply determined from change in velocity
Δe=(v₂²-v₁²)/2
Put the given values to find the specific energy change
Δe=0.578 kJ/kg
Answer:
t = 0.55[sg]; v = 0.9[m/s]
Explanation:
In order to solve this problem we must establish the initial conditions with which we can work.
y = initial elevation = - 1.5 [m]
x = landing distance = 0.5 [m]
We set "y" with a negative value, as this height is below the table level.
in the following equation (vy)o is equal to zero because there is no velocity in the y component.
therefore:
Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.
Answer:
Explanation:
It is given that,
Length of the coil, l = 3 cm = 0.03 m
Area of cross section of the coil,
Number of turns in the coil, N = 300
inductance of the coil is
So, the inductance of the coil is 1.88× 10⁻⁴H