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ziro4ka [17]
3 years ago
9

Explain why a car driving around a curve at a constant speed is accelerating.

Physics
1 answer:
GREYUIT [131]3 years ago
7 0
But the fact is that an accelerating object is an object that is changing it’s velocity.. for this reason , it can be safely concluded that an object moving in a circle at constant speed is indeed accelerating. It is accelerating because the direction of the velocity vector is changing .
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when a solid wheel rotates about a fixed axis do all of the points of the wheel have the same tangential speed?
vitfil [10]

Yes they should all be going the same speed.


Hope this helped :)

3 0
3 years ago
Read 2 more answers
Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to t
yarga [219]

Answer

The rate at which the magnetic field is changing is  [\frac{dB}{dt} ] =  0.000467 T/s

Explanation

From the question we are told that

   The electric field strength is E =  3.5mV/m =  3.5 *10^{-3} \ V/m

    The radius is  r =  1.5 \ m

The rate of change of the  magnetic  field  is mathematically represented as

        \frac{d \phi }{dt}  =  \int\limits^{} {E \cdot dl}

Where dl is change of a unit length

     \frac{d \phi}{dt}  =  A *  \frac{dB}{dt}

Where A is the area which is mathematically represented as

     A = \pi r^2

    So

    E \int\limits^{} {  dl} =  ( \pi r^2) (\frac{dB}{dt} )  

  E L  =  ( \pi r^2) (\frac{dB}{dt} )  

where L is the circumference of the circle which is mathematically represented as

     L = 2 \pi r

So

     E (2 \pi r ) =  (\pi r^2 ) [\frac{dB}{dt} ]

      E  =   \frac{r}{2}  [\frac{dB}{dt} ]

       [\frac{dB}{dt} ] = \frac{E}{ \frac{r}{2} }

substituting values

      [\frac{dB}{dt} ] = \frac{3.5 *10^{-3}}{ \frac{15}{2} }

      [\frac{dB}{dt} ] =  0.000467 T/s    

8 0
3 years ago
In the nucleus of all atoms are sub-atomic particles called protons and neutrons. all protons have a positive charge. since all
murzikaleks [220]

Protons stay close together in the nucleus because the strong nuclear force.


There are four natural elemental forces: 1) gravity, 2) electromagnetic force, 3) weak nuclear force, and 4) strong nuclear force.


Gravity is an attractive force. It acts at long distance and is proportion to the product of the masses. It is not relevant in the nucleous of an atoms because the masses are tiny.


Electrotmagnetic force may be attractive or repulsive. Indeed, as stated since the protons have all positive charge, this force is repulsive, and you could expect that they the protons cannot stand so close to each other in the nucleous.


Strong nuclear force is the strongest of the four forces in nature and acts only to very short distances. It is the atractive force between the partilces in the atom nuclei. This force overcomes the electromagnetic repulsion between the protons. This force is responsible for keeping the protons and the neutrons together in the nuclei.

6 0
4 years ago
B. the hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration,
balu736 [363]

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2  m/s^{2}

v^{2} = u^{2} + 2as

0 =  (9.5)^{2} + 2* (- 9.5 /2) * s

-  (9.5)^{2}  = - 9.5 s

s = 9.5 m

To learn more about kinematics here

brainly.com/question/27126557

#SPJ4

3 0
2 years ago
A force of 333 N is applied 33 cm from the pivot point. What is the maximum torque of this situation
exis [7]

Answer: 109.89 Nm

Explanation:

The maximum torque will be calculated as the force multiplied by the perpendicular distance. This will be:

Torque = force × perpendicular distance

torque = 333 × 0.33

= 109.89 Nm

5 0
3 years ago
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