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4 years ago

Nuclear sizes are expressed in a unit named Magnetism at the centre of a bar magnet is

Physics

2 answers:

serg [7]4 years ago

6 0

The first one is fermi and the other one is zero
hope this helps

Illusion [34]4 years ago

3 0

Nuclear size are measured in a unit called fermi
Magnetism at the centre of a bar magnet is zero, because there is no magnetism at all in the centre
Hope this helps :)

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To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof

BlackZzzverrR [31]

<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (1)

$V_{f}=V_{o}+at$ (2)

Where:

$V_{f}$ is the final velocity of the plane (the takeoff velocity in this case)

$V_{o}=0$ is the initial velocity of the plane (we know it is zero because it starts from rest)

$a=5m/s^{2}$ is the constant acceleration of the plane to reach the takeoff velocity

$d=1800m$ is the distance of the runway

$t$ is the time

Knowing this, let's begin with (1):

${V_{f}}^{2}=0+2(5m/s^{2})(1800m)$ (3)

${V_{f}}^{2}=18000m^{2}/s^{2}$ (4)

$V_{f}=134.164 m/s$ (5)

Substituting (5) in (2):

$134.164 m/s=0+(5m/s^{2})t$ (6)

Finding $t$ :

$t=26.8 s$ This is the time needed to take off

6 0

3 years ago

The speed or celerity of deep-water waves... A. increases with increasing water depth B. increases as water becomes blue in colo

antoniya [11.8K]

Answer:

Explanation:

The speed or celerity of deep-water waves increases with increasing water depth.

With increase in depth, the pressure inside the increases as p=ρgh.

And with this increase in pressure force associated with waves increase because force is directly proportional to the pressure. Now greater the force greater will be accleration and greater velocity is obtained.

4 0

3 years ago

A 0.30 kg yo-yo consists of two solid disks of radius 5.10 cm joined together by a massless rod of radius 1.0 cm and a string wr

docker41 [41]

Answer:

0.70046 m/s²

2.732862 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of yo-yo = 0.3 kg

R = Radius of rolling disk = 5.1 cm

r = Radius of rod = 1 cm

For a rolling disks the acceleration is given by

$a=\frac{g}{1+\frac{R^2}{2r}}\\\Rightarrow a=\frac{9.81}{1+\frac{0.051^2}{2\times 0.01^2}}\\\Rightarrow a=0.70046\ m/s^2$

The acceleration of the yo-yo is 0.70046 m/s²

The tension in the string will be

$T=m(g-a)\\\Rightarrow T=0.3\times (9.81-0.70046)\\\Rightarrow T=2.732862\ N$

The tension in the string is 2.732862 N

8 0

3 years ago

Why are identical bulbs arranged in a series circuit with a battery less bright than those arranged in a parallel circuit with t

tatuchka [14]

Explanation:

Resistors connected in series obey the following equation:

$R_{\rm eq} = R_1 + R_2 + R_3 + ...$

Resistors connected in parallel obey the following equation:

$\frac{1}{R_{\rm eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...$

The total current of the circuit will obey the Ohm's Law: V = IR. And the current will be divided across the resistors (bulbs) depending on their resistances. So, if a bulb has a higher resistance, then its current will be lesser, and it will be less bright. If a bulb has a lower resistance, then its current will be higher, and it will be brighter.

According to the above resistances connected in series and parallel, clearly, the resistances (bulbs) connected in series will have more resistance in total, and therefore less current will flow across them, and they will be less bright.

6 0

3 years ago

"Calculate the frequency of infrared light with wavelength of 9.50 x 10-7m"

densk [106]

Answer:

The frequency of the infrared light is approximately 3.156 × 10¹⁴ Hz

Explanation:

Given that the wavelength of infrared light, λ = 9.50 × 10⁻⁷ m, we have;

The speed of light (which is constant), c = v × λ = 299,792,458 m

Where v = The frequency of the infrared light, we have;

v = c/λ = 299,792,458/(9.50 × 10⁻⁷) ≈ 3.156 × 10¹⁴ Hz

The frequency of the infrared light = v ≈ 3.156 × 10¹⁴ Hz.

8 0

3 years ago