Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
I believe the answer is 0
i can help if you have the picture
First, make sure that all the variables are in one side. The first equation is gonna be x-y=3
Second, we are going to eliminate the y because it is much easier, but you can also eliminate the x
We have to add both equation because the y in the first equation is negative and in the second equation it’s positive.
We are left with 3x=9
Therefore, x=3
Last, substitute x= 3 in one of the equations
Y=6
P.O.I is (3,6)
$15 more, than twice Friday's earnings
d is how much he earned on Friday
s is how much he earned on Saturday
2d + 15 = s
