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3 years ago

What is the distance between the coordinates (9, 10) and (10, 2)?

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

Answer:

yes that's correct I offer to factor out

guajiro [1.7K]3 years ago

6 0

Answer:

7 units

Step-by-step explanation:

10 is the same distance so you would subtract

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PLEASE HELP i will give you a brainly

Lady bird [3.3K]

Answer:JKL and ∠RST are complementary.

m∠JKL = 36° and m∠RST = ( x + 15)°.

Find the value of x and the measure of ∠RST .

complementary angles are two angles whose sum is 90°

36%2Bx+%2B+15=90°

51%2Bx+=90°

x+=90-51°

x+=39°

->the measure of ∠RST== ( 39 + 15)=54°

both answer and explanation

8 0

3 years ago

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

jaimie ran 3 1/2 on monday.She ran half as far on teusday as she did on monday.How far did jaimie run in all on monday and teusd

Soloha48 [4]

Answer: 5 1/4

Step-by-step explanation:

hope this helps!

4 0

2 years ago

~Help me with this please I will mark as BRANLIEST and give you 55 POINTS! (If you answer correctly)

kolezko [41]

Answer:

$y=50x+75$

Step-by-step explanation:

When writing a linear equation from a graph, we need to find two things: the y-intercept (what y is when x is 0) and the slope.

First, let us find the y-intercept.

To do this, we can just look at the graph. When x=0, y=75, so 75 is our y-intercept, which is also known as b.

To find the slope of this line, we will need to look at two points

We already know that (0,75) is a point. From the graph, we can see that (1,125) is also a point on this line.

Now, we can find the slope of this line using the following formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{125-75}{1-0} \\\\m=\frac{50}{1} \\\\m=50$

Now that we have both the y-intercept and slope, we can put them together in the form of $y=mx+b$

$y=50x+75$

5 0

3 years ago

What is the value of the fourth term in a geometric sequence for which ay =

enot [183]

Answer:

a₄ = 1.25

Step-by-step explanation:

Given that,

First term of GP, a₁ = 10

The common ration of GP, r = 0.5

The nth term of the GP is given by :

$a_4=a_1r^{n-1}\\\\a_4=a_1r^3\\\\a_4=10\times (0.5)^3\\\\a_4=10\times 0.125\\\\a_4=1.25$

So, the fourth term of the GP is 1.25.

5 0

3 years ago