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Yuki888 [10]
3 years ago
14

if the computer screen shows this image as calinda is downloading a file, how big is the file she’s loading ?

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

the file is 20 kb

Step-by-step explanation:

16kb/80%

xkb/100%

1600=80%

80       80

20KB

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A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?
Alexxandr [17]

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

(x-h)^2+(y-k)^2=r^2

Where the center of a circle is (h,k) and r is the radius of the circle.  In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9.  However, since the standard equation states that we must write r in the form of r^2 this means that r^2=9^2.  Therefore by plugging in the values we have:

(x-0)^2+(y-0)^2=9^2\\\\x^2+y^2=9^2

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Perform the following operations and write the answers in radical form. Part A:√7+√3+√98−√18 Part B:3√5−3√11+2√121−3√90
Sveta_85 [38]

Answer:

  1. \sqrt{7}+\sqrt{3}+4\sqrt{2}
  2. 3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Part A ;

\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}

Part B ;

3\sqrt{5}  - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

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