Solve the square root equation 5-2√x=11

Mathematics

2 answers:

sasho [114]3 years ago

5 0

Answer: i tried hopes this help if it does not srry

Step-by-step explanation:

riadik2000 [5.3K]3 years ago

4 0

Answer: Hmm There's no solution

Step-by-step explanation: Have a nice brilliant day!

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At Best Burgers, Jack collected sales data on the type of side order served with each type of burger purchased for a week. Jack

horsena [70]

The <em><u>correct answers</u></em> are:

60 pounds of onion rings and 60 hamburgers.

Explanation:

Jack serves a half pound of onion rings with every burger. He serves 120 bacon cheeseburgers. To find the number of pounds of onion rings, we multiply 1/2 pound by 120 burgers:

1/2(120) = 1/2(120/1) = (1*120)/(2*1) = 120/2 = 60 pounds of onion rings.

There were 8 hamburgers served out of the first 40 orders. If this rate continues, then to find the number of hamburgers out of 300 orders, we multiply 8/40 by 300:

8/40(300) = 8/40(300/1) = (8*300)/(40*1) = 2400/40 = 60

There would be 60 hamburgers.

4 0

3 years ago

Read 2 more answers

Pleasee Help!

Anna11 [10]

America wont have a wall next to america and peace would've been made

6 0

3 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$