Determine the exact and approximate circumference of the circle.
1 answer:
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Answer:
D
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 6, - 8), thus
(x + 6)² + (y + 8)² = r²
The radius is the distance from the centre to a point on the circle
Calculate r using the distance formula
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 6, - 8) and (x₂, y₂ ) = (0, 0)
r = =
=
= 10
Hence
(x + 6)² + (y + 8)² = 100 → D
Answer:
0.2146
Step-by-step explanation:
From the picture:
The radius of the circle = r. This means that the area of the circle = πr²
Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²
The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²
The ratio of the area inside the square but outside the circle to the area of the square = r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146
The value of f(a)=4-2a+6, f(a+h) is
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6()
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6
)]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Learn more about function at brainly.com/question/10439235
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