Answer:
(2, -5)
Step-by-step explanation:
Convert to vertex form:
3x^2 - 12x + 7
= 3(x^2 - 4x) + 7
Completing the square:
= 3[ (x - 2)^2 - 4)] + 7
= 3(x - 2)^2 - 12 + 7
= 3(x - 2)^2 - 5.
Comparing with the general form
a(x - b)^2 + c we see that the vertex is (b, c) = (2, -5).
Answer:
21,000
Step-by-step explanation:
........................
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
C, adding the rest of this sentence because it needs to be longer
