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3 years ago

6

Solve –2x2 – 16x – 44 = 0 answer please using quadtratic equation ...?

1 answer:

alexira [117]3 years ago

5 0

The quadratic formula is one way to obtain the solution of the quadratic<span> equation. It is expressed as:

x = (-b +/- </span>√b² - 4ac ) / 2a

where, for this problem, a = -2, b = -16 and c = -44.

We solve as follows:

x = (-b +/- √b² - 4ac ) / 2a
x = (-(-16) +/- √(-16)² - 4(-2)(-44) ) / 2(-2)
x = (16 +/- √256 - 352 ) / -4
x = (16 +/- √-96 ) / -4
x = -(16 +/- 4i√6 ) / 4

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

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The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

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Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

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In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

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The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

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3 years ago