Answer:
C.
Step-by-step explanation:
It does not have to be April if there are 30 days. If its not April, it can still have 30 days. April does have 30 days.
The solution is B = 43
Step-by-step explanation:
Simplify and solve for the unknown for 5(B + 3) = 4(B - 7) + 2B
- Simplify each side
- Add the like terms in each side if need
- Separate the unknown in one side and the numerical term in the other side to find the value of the unknown
∵ 5(B + 3) = 4(B - 7) + 2B
- Multiply the bracket (B + 3) by 5 in the left hand side and multiply
the bracket (B - 7) by 4 in the right hand side
∵ 5(B + 3 ) = 5(B) + 5(3) = 5B + 15
∵ 4(B - 7) = 4(B) - 4(7) = 4B - 28
∴ 5B + 15 = 4B - 28 + 2B
- Add the like terms in the right hand side
∵ 4B + 2B = 6B
∴ 5B + 15 = 6B - 28
- Add 28 to both sides
∴ 5B + 43 = 6B
- Subtract 5B from both sides
∴ 43 = B
- Switch the two sides
∴ B = 43
To check the answer substitute the value of B in each side if the two sides are equal then the solution is right
The left hand side
∵ 5(43 + 3) = 5(46) = 230
The right hand side
∵ 4(43 - 7) + 2(43) = 4(36) + 86 = 144 + 86 = 230
∴ L.H.S = R.H.S
∴ The solution B = 43 is right
The solution is B = 43
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Option D
I hope that is right
Answer:
The fourth term is -102----------------------------------------------
Explanation:
The term after the nth term is generated by this rule
which means that we first
Step 1) multiply the nth term (
) by -4
Step 2) Add the result of step 1 to the value 2 to get the next term in the sequence
Let's follow those steps above to generate the first four terms
The first term is
. In short, the first term is 2
The second term is...
So the second term is -6
The third term is...
The third term is 26
Finally, the fourth term is...
The fourth term is -102.
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
