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Zina [86]
3 years ago
13

How do u type negative one on here

Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

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If we run the following line:<br> y = int(3 * '4')<br><br> what is the value of y?
Hitman42 [59]

The value of y in the code segment is 444

<h3>How to determine the value of y?</h3>

The code segment is given as:

y = int(3 * '4')

Evaluate the expression in the bracket

y =int('444')

Remove the bracket

y = 444

Hence, the value of y in the code segment is 444

Read more about code segments at:

brainly.com/question/26683418

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What is the solution for x in the equation?<br><br> 10x − 4.5 + 3x = 12x − 1.1
Aleksandr [31]

Answer:in first part of equation add 10x and 3x (like terms)

13x-4.5=12x-1.1

move all terms containing x to left side of equation

13x-4.5-12x= -1.1

x-4.5= -1.1

Subtract 4.5 from both sides

x=3.4

Step-by-step explanation:

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3 years ago
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Mrs. Datz had to make a visit to the bank because her account was overdrawn
Alexeev081 [22]

Answer:

The answer of this question is $68.

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A towns population went from 25800 to 42600 in 15 years. What was the percent of change
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42600-25800=16800
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4 0
3 years ago
Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1
Mumz [18]
x^2+64=x^2-(8i)^2=(x-8i)(x+8i)

16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)

(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi

(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi

(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i


Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2
4 0
3 years ago
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