Answer:
Step-by-step explanation:
Given that spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as
S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}.
If the random variable is “yellow (Y),” let us first find the values that Y can take.
From the sample space given above, we find that Y can take only 3 values 0,1,2
In the sample space of 16 entries, Y occurs 0 times in 9 times
1 time in 6 times and 2 times 1 time
Hence probability = no of favouable outcomes/number in sample space
So
P(Y=0) = 9/16
P(Y=1) = 6/16 = 3/8
P(Y=2) = 1/16
