I don't know any <em><u>slick</u></em> way to do this. I would just list the prime numbers
between 40 and 50 and test them one at a time.
The prime numbers between 40 and 50 are: 41, 43, 47
<u>Test 41:</u>
-- add 1 . . . 42
-- prime factors of 42 . . . 2, 3, 7
-- sum of the factors . . . 12
<u>Test 43:</u>
-- add 1 . . . 44
-- prime factors of 44 . . . 2, 11
-- sum of the factors . . . 13
<u>Test 47:</u>
-- add 1 . . . 48
-- prime factors of 48 . . . 2, 3,
-- sum of the factors . . . 5
Maybe I'm not understanding how to list prime factors, but so far,
I haven't found any number that answers the question.
Maybe if I write the prime factorization of 44 like this:
44 = 2 * 2 * 11
Now the items in the prime factorization do add up to 15.
So the answer would seem to be <em>43.</em>
1/3 of 45 is 15, meaning 15 students gave their speech on day 1
Today 2/5 of the remaining students gave their speech. That’s 12 more
So a total of 27 students gave their speeches. That means 18 students remain. The answer is 18
Answer:
C. 94.2 cm
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
Step-by-step explanation:
<u>Step 1: Define</u>
r = 15 cm
<u>Step 2: Find </u><em><u>C</u></em>
- Substitute [C]: C = 2π(15 cm)
- Multiply: C = 30π cm
- Multiply: C = 94.2 cm
Answer: what the question based on?
Step-by-step explanation:
