Answer:
f(n) = f(n - 1) + 3
Step-by-step explanation:
Substitute
to get the recursive formula.
OPTION 1: f(n) = f(n - 1) + 3
Substituting n = 1.
f(1) = f(1 - 1) + 3 = 0 + 3 = 3.
Substituting n = 2.
f(2) = f(2 - 1) + 3 = f(1) + 3 = 3 + 3 = 6.
Substituting n = 3.
f(3) = f(3 - 1) + 3 = f(2) + 3 = 6 + 3 = 9.
The numbers match the given sequence. So, we say the above recursive formula represents the sequence.
OPTION 2: f(n) = f(n - 1) + 2
Substituting n = 1
f(1) = f(0) + 2
3.
So, this is eliminated.
Similarly, OPTION 3 and OPTION 4 can be eliminated as well.
Answer:

Step-by-step explanation:
![S= \frac{n}{2 [2a + (n - 1)d]}](https://tex.z-dn.net/?f=S%3D%20%5Cfrac%7Bn%7D%7B2%20%5B2a%20%2B%20%28n%20-%201%29d%5D%7D)
Simplifying the fraction by multiplying d into the (n-1) term,
![s=\frac{n}{2 [2a + (n - 1)d] } = \frac{n}{2[2a + dn - d] }](https://tex.z-dn.net/?f=s%3D%5Cfrac%7Bn%7D%7B2%20%5B2a%20%2B%20%28n%20-%201%29d%5D%20%7D%20%3D%20%5Cfrac%7Bn%7D%7B2%5B2a%20%2B%20dn%20-%20d%5D%20%7D)
Simplifying the fraction by multiplying 2 throughout,

Multiply
on both sides

Cancel the
on the right hand side

Multiply s to the terms,

Move
to the right hand side by subtracting
on both sides

On the right hand side of the equation, take out 

Divide Left hand side by
,

Answer:
- rational
- irrational
- irrational
- irrational
- √7, it is irrational
Step-by-step explanation:
A <em>rational</em> number is one that can be expressed as the ratio of two integers. All fractions that have integer numerators and (non-zero) denominators are <em>rational</em> numbers. Any finite decimal number, or any repeating decimal number, is a rational number. These can always be expressed as the ratio of two integers. For example, 0.4040... = 40/99, and 0.286 = 286/1000.
To make an irrational sum, at least one of the contributors must be irrational. You want an irrational 2-number sum that has 7/8 as one of the contributors. Since 7/8 is rational, the other contributor must be irrational.
__
<u>Step 1</u>. The number 7/8 is <em>rational</em>.
<u>Step 2</u>. The desired sum is <em>irrational</em>.
<u>Step 3</u>. The rule <em>rational + </em><em>irrational</em><em> = irrational</em> applies.
<u>Step 4</u>. An <em>irrational</em> number must be chosen.
Step 5. √7 will produce an irrational sum, because <em>it is irrational</em>.