All these equations are in the form of ax^2 + bx + c = 0, where a, b, and c are some numbers. the discriminants of equations like this are equal to b^2 - 4ac. if the discriminant is negative, there are two imaginary solutions. if the discriminant is positive, there are two real solutions. if the discriminant is 0, there is one real solution.
<span>x^2 + 4x + 5 = 0
</span>b^2 - 4ac
4^2 - 4(1)(5)
16-20
-4, two imaginary solutions.
<span>x^2 - 4x - 5 = 0
</span>b^2 - 4ac
(-4)^2 - 4(1)(-5)
16 + 20
36, two real solutions.
<span>4x^2 + 20x + 25 = 0
</span>b^2 - 4ac
20^2 - 4(4)(25)
400 - 400
0, one real solution.
If you use BEDMAS you should end up with an answer of 1004.
Answer:
the answer is=21
Step-by-step explanation:
u have to sum all of its sides
(length+breadth+height).
Use c^2=a^2+b^2
26^2= 13^2 + b^2
676=169 + b^2 (subtract 169 from both sides)
507= b^2 (take the square root of each side)
22.52 in. =b
